B and C Blocks reviewed the idea of projectiles launched horizontally and had class time to work practice problems for this type of motion. Remember that time is y-dependent and the most commonly used formula to find time for these problems is Δy = vot + 1/2at2. Since the initial velocity in the y-direction is 0 m/s, the formula simplifies to: Δy = 1/2at2. Once you have time, solving for horizontal aspects of the motion is simple. You've got one formula to use: vx = Δx/t. You're generally asked for either horizontal displacement (and they give you vx) or for launch velocity (and they give you Δx). Just use the time you found for the y-component of the motion and you're good as gold. We'll look over these tomorrow and then start to discuss projectiles launched at an angle. They take a bit more work, but it builds on what we've already done, so it won't be exhausting.
E Block had their full horizontally-launched projectiles chat today and also has a set of problems to work. We'll be going over those on Monday, since tomorrow is your lab block. I'd get them out of the way tonight for two reasons:
- They will help you with you lab calculations tomorrow.
- You'll have the lab write-up to do over the weekend, so don't give yourself double homework.
For everyone, the test is looking like it will be next Friday. That's a little later than I had planned but we're losing a couple of periods next week for various things, so c'est la vie...
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