vx = 20 m/s(cos 30°)
vi,y = 20 m/s(sin 30°)
right off the bat. Then, just make sure to use the proper velocity component when you work in the x- or y-directions. Another helpful trick is to break the parabola in two. This can make solving for time in the air simple. Solve for time for one-half of the parabola and then multiply times two to get full time in the air. Then, with that time, finding horizontal range is super simple (vx = Δx/t). Different groups have different problems that they are working on tonight, and we will check over them tomorrow before moving forward. If more practice is needed, we'll take the time to do that. C Block will be doing a lab on horizontally-launched projectiles and some groups may dip toes in relative motion, depending on quickly we move through our projectiles review. Test on Friday and the Chapter 3 review sheet is up on Edline. Then - Forces!
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